2023 Easy Success Oracle 1z0-071 Exam in First Try [Q56-Q74]

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2023 Easy Success Oracle 1z0-071 Exam in First Try

Best 1z0-071 Exam Dumps for the Preparation of Latest Exam Questions

Oracle 1z1-071 certification exam is an excellent opportunity for professionals who want to validate their knowledge and skills in SQL programming language. Oracle Database SQL certification exam is globally recognized and highly valued by employers in the IT industry. By passing 1z0-071 exam, candidates can enhance their career prospects and can increase their chances of getting hired for high-paying jobs in the database administration and development field.

Oracle Database SQL exam is a multiple-choice exam consisting of 73 questions that must be completed within 100 minutes. 1z0-071 exam is available in English and Japanese languages. 1z0-071 exam covers a wide range of topics, including data manipulation, database design, database objects, and more. 1z0-071 exam is designed to test your knowledge of SQL and your ability to apply it to real-world scenarios.

QUESTION 56
Examine the structure of the PROGRAMS table:

Which two SQL statements would execute successfully? (Choose two.)

SELECT NVL(ADD_MONTHS(END_DATE,1)SYSDATE)FROM programs;

SELECT TO_DATE(NVL(SYSDATE-END_DATE,SYSDATE))FROM programs;

SELECT NVL(MONTHS_BETWEEN(start_date,end_date),’Ongoing’)FROM programs;

SELECT NVL(TO_CHAR(MONTHS_BETWEEN(start-date,end_date)),’Ongoing’)FROM programs;

QUESTION 57
You need to display the date 11-oct-2007 in words as ‘Eleventh of October, Two Thousand Seven’.
Which SQL statement would give the required result?

SELECT TO_CHAR(TO_DATE(’11-oct-2007′), ‘fmDdthsp “of” Month, Year’)FROM DUAL;

SELECT TO_CHAR(’11-oct-2007′, ‘fmDdspth “of” Month, Year’)FROM DUAL;

SELECT TO_CHAR(TO_DATE(’11-oct-2007′), ‘fmDdspth of month, year’)FROM DUAL;

SELECT TO_DATE(TO_CHAR(’11-oct-2007′), ‘fmDdspth “of” Month, Year’))FROM DUAL;

QUESTION 58
Examine this SELECT statement and view the Exhibit to see its output:

SELECT constraints_name, constraints_type, search_condition, r_constraint_name, delete_rule, status,
FROM user_constraints
WHERE table_name = ‘ORDERS’;
Which two statements are true about the output? (Choose two.)

The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.

The R_CONSTRAINT_NAME column contains an alternative name for the constraint.

In the second column, ‘c’ indicates a check constraint.

The STATUS column indicates whether the table is currently in use.

QUESTION 59
View the Exhibit and examine the structure of CUSTOMERStable.
Using the CUSTOMERStable, you need to generate a report that shows an increase in the credit limit by
15% for all customers. Customers whose credit limit has not been entered should have the message “Not Available” displayed.
Which SQL statement would produce the required result?

SELECT NVL (TO CHAR(cust_credit_limit * .15), ‘Not Available’) “NEW CREDIT”

FROM customers;
SELECT TO_CHAR (NVL(cust_credit_limit * .15), ‘Not Available’) “NEW CREDIT”

FROM customers;
SELECT NVL(cust_credit_limit * .15), ‘Not Available’) “NEW CREDIT”

FROM customers;
SELECT NVL(cust_credit_limit), ‘Not Available’) “NEW CREDIT”

FROM customers;

QUESTION 60
View the Exhibit and examine the structure in the EMPLOYEEStables.

Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id= 90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id= 10;
What would be the outcome of the above SQL statement?

The statement would not execute because the positional notation instead of the column name should be used with the ORDER BYclause.

The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.

The statement would execute successfully but it will ignore the ORDER BYclause and display the rows in random order.

The statement would not execute because the ORDER BYclause should appear only at the end of the SQL statement, that is, in the last SELECTstatement.

QUESTION 61
Examine the structure of the PROGRAMS table:

Which two SQL statements would execute successfully?

SELECT NVL (ADD_MONTHS (END_DATE,1) SYSDATE) FROM programs;

SELECT TO_DATE (NVL (SYSDATE-END_DATE, SYSDATE)) FROM programs;

SELECT NVL (MONTHS_BETWEEN (start_date, end_date), ‘Ongoing’) FROM programs;

SELECT NVL (TO_CHAR (MONTHS_BETWEEN (start-date, end_date)), ‘Ongoing’) FROM programs

QUESTION 62
View the exhibit and examine the description for the SALESand CHANNELStables.

You issued this SQL statement:

Which statement is true regarding the result?

The statement will fail because the subquery in the VALUESclause is not enclosed within single quotation marks.

The statement will fail because a subquery cannot be used in a VALUESclause.

The statement will fail because the VALUESclause is not required with a subquery.

The statement will execute and a new row will be inserted in the SALEStable.

QUESTION 63
Examine this description of the PRODUCTStable:

Rows exist in this table with data in all the columns. You put the PRODUCTStable in read-only mode.
Which three commands execute successfully on PRODUCTS? (Choose three.)

DROP TABLE products;

ALTER TABLE products DROP COLUMN expiry_date;

ALTER TABLE products SET UNUSED (expiry_date);

ALTER TABLE products DROP UNUSED COLUMNS;

CREATE INDEX price_idx ON products (price);

TRUNCATE TABLE products;

QUESTION 64
View the Exhibit and examine the structure of ORDERS and ORDER_ITEMS tables.
ORDER_ID is the primary key in the ORDERS table. It is also the foreign key in the ORDER_ITEMS table wherein it is created with the ON DELETE CASCADE option.
Which DELETE statement would execute successfully?

DELETE orders o, order_items IWHERE o.order_id = i.order_id;

DELETEFROM ordersWHERE (SELECT order_idFROM order_items);

DELETE ordersWHERE order_total < 1000;

DELETE order_idFROM ordersWHERE order_total < 1000;

QUESTION 65
Examine the description of the CUSTOMERS table:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?

SELECT * FROM customers WHERE city =’D_%’;

SELECT * FROM customers WHERE city =’%D_’;

SELECT * FROM customers WHERE city LIKE’D %’;

SELECT * FROM customers WHERE city LIKE’D_’;

QUESTION 66
Examine this business rule:
Each student can work on multiple projects and each project can have multiple students.
You must design an Entity Relationship(ER) model for optimal data storage and allow for generating reports in this format:

Which two statements are true?

An associative table must be created with a composite key of STUDENT_ID and PROJRCT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.

PROJECT_ID must be the primary key in the PROJECTS entity and foreign key in the STUDENTS entity.

The ER must have a 1-to-many relationship between the STUDENTS and PROJECTS entities.

The ER must have a many to-many relationship between the STUDENTS and PROJECTS entities that must be resolved into 1-to-many relationships.

STUDENT ID must be the primary key in the STUDENTS entity and foreign key in the PROJECTS entity.

QUESTION 67
Which statement is true about SQL query processing in an Oracle database instance? (Choose the best answer.)

During parsing, a SQL statement containing literals in the WHERE clause that has been executed by any session and which is cached in memory, is always reused for the current execution.

During executing, the oracle server may read data from storage if the required data is not already in memory.

During row source generation, rows that satisfy the query are retrieved from the database and stored in memory.

During optimization, execution plans are formulated based on the statistics gathered by the database instance, and the lowest cost plan is selected for execution.

QUESTION 68
Examine the structure of the EMPLOYEES table. (Choose two.)

You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output?

SELECT MIN(Salary) minsal, MAX(salary) maxsalFROM employeesWHERE hire_date < SYSDATE-365GROUP BY MIN(salary), MAX(salary);

SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsal FROM employeesWHERE hire_date < SYSDATE-365)GROUP BY maxsal, minsal;

SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsal FROM employeesWHERE hire_date < SYSDATE-365GROUP BY MIN(salary), MAX(salary);

SELECT MIN(Salary), MAX(salary)FROM (SELECT salary FROM employeesWHERE hire_date < SYSDATE-365);

QUESTION 69
Examine the description of the EMPLOYEEStable:

Which query is valid?

SELECT dept_id, MAX(AVG(salary)) FROM employees GROUP BY dept_id;

SELECT dept_id, AVG(MAX(salary)) FROM employees GROUP BY dept_id;

SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id,
join_date;

SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id;

QUESTION 70
The SALES table has columns PROD_IDand QUANTITY_SOLDof data type NUMBER.
Which two queries execute successfully? (Choose two.)

SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING

COUNT(*) >10;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP

BY prod_id HAVING COUNT(*) >10;
SELECT COUNT (prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY

prod_id;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP

BY COUNT(*) >10;
SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;

QUESTION 71
You must create a SALES table with these column specifications and data types: (Choose the best answer.) SALESID: Number
STOREID: Number
ITEMID: Number
QTY: Number, should be set to 1 when no value is specified
SLSDATE: Date, should be set to current date when no value is specified PAYMENT: Characters up to 30 characters, should be set to CASH when no value is specified Which statement would create the table?

CREATE TABLE Sales
(SALESID NUMBER (4),
STOREID NUMBER (4),
ITEMID NUMBER (4),
QTY NUMBER DEFAULT = 1,
SLSDATE DATE DEFAULT SYSDATE,
PAYMENT VAR
CHAR2(30) DEFAULT = “CASH”);

CREATE TABLE Sales
(SALESID NUMBER (4),
STOREID NUMBER (4),
ITEMID NUMBER (4),
QTY NUMBER DEFAULT = 1,
SLSDATE DATE DEFAULT ‘SYSDATE’,
PAYMENT VARCHAR2(30) DEFAULT CASH);

CREATE TABLE Sales
(SALESID NUMBER (4),
STOREID
NUMBER (4),
ITEMID NUMBER (4),
qty NUMBER DEFAULT = 1,
SLSDATE DATE DEFAULT SYSDATE,
PAYMENT VARCHAR2(30) DEFAULT = “CASH”);

Create Table sales
(salesid NUMBER (4),
Storeid NUMBER (4),
Itemid NUMBER (4),
QTY NUMBER DEFAULT 1,
Slsdate DATE DEFAULT SYSDATE,
payment VARCHAR2(30) DEFAULT ‘CASH’);

QUESTION 72
You execute this command:
ALTER TABLE employees SET UNUSED (department_id);
Which two are true?

A query can display data from the DEPARTMENT_ID column.

The storage space occupied by the DEPARTMENT_ID column is released only after a COMMIT is issued.

The DEPARTMENT_ID column is set to null for all tows in the table

A new column with the name DEPARTMENT_ID can be added to the EMPLOYEES table.

No updates can be made to the data in the DEPARTMENT_ID column.

The DEPARTMENT_ID column can be recovered from the recycle bin

QUESTION 73
Examine the description of the CUSTOMERStable:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two characters.
Which query can be used?

SELECT * FROM customers WHERE city = ‘D_%’;

SELECT * FROM customers WHERE city LIKE ‘D_’;

SELECT * FROM customers WHERE city LIKE ‘D_%’;

SELECT * FROM customers WHERE city = ‘%D_’;

QUESTION 74
You own table DEPARTMENTS, referenced by views, indexes, and synonyms.
Examine this command which executes successfully:
DROP TABLE departments PURGE;
Which three statements are true?

Neither can it be rolled back nor can the DEPARTMENTS table be recovered.

It will remove all views that are based on the DEPARTMENTS table.

It will delete all rows from the DEPARTMENTS table, but retain the empty table.

It will remove the DE PARTMENTS table from the database.

It will remove all synonyms for the DEPARTMENTS table.

It will drop all indexes on the DEPARTMENTS table.

Passing this Oracle exam means that you are on the way of getting the following credentials:

Oracle Database SQL Certified Associate
Oracle Database 12c Administrator Certified Associate;

Completing 1Z0-071 is enough to obtain the first certificate of the associate level, while for gaining the second one in the Oracle Database 12c Administrator track, passing the 1Z0-062 exam is a necessity. Anyway, having any of these certifications on your CV will show your employer your ability to apply SQL knowledge for the Oracle Database server maintenance.

1z0-071 Study Material, Preparation Guide and PDF Download: https://www.testkingfree.com/Oracle/1z0-071-practice-exam-dumps.html